Answer:
The density of charge carriers in the conductor is [tex]6.7\times10^{27}\ charge/m^3[/tex]
(d) is correct option.
Explanation:
Given that,
Current = 2.0 A
Thickness = 0.50 mm
Hall voltage [tex]v= 4.5\times10^{-6}\ V[/tex]
Magnetic field = 1.2 T
We need to calculate the density of charge carriers in the conductor
Using formula of the density of charge
[tex]V_{h}=\dfrac{iB}{neL}[/tex]
[tex]n=\dfrac{iB}{eVL}[/tex]
Where, i = current
B = magnetic filed
V = voltage
L = thickness
Put the value into the formula
[tex]n=\dfrac{2.0\times1.2}{1.6\times10^{-19}\times0.50\times10^{-3}\times4.5\times10^{-6}}[/tex]
[tex]n=6.7\times10^{27}\ charge/m^3[/tex]
Hence, The density of charge carriers in the conductor is [tex]6.7\times10^{27}\ charge/m^3[/tex]
