Answer:
[tex]5.00x10^{3} Kg[/tex]
Explanation:
There are two reactions taking place and the product of the first is a reactant at the other, so writing down the balanced chemical equations is the first step in determinimg the proportions
1) C + O2 → CO2
1. Molar mass C = 12.0107 g/mol
2. Number of moles [tex]1.00x10^{3} Kg[/tex] of carbon has [tex]8.33x10^{4} mol[/tex] of C
Remember: mol(n)
[tex]n=\frac{sample mass}{molar mass}[/tex]
2) CO2 + 2NH3 → CO(NH3)2 + H2O
1. Molar mass CO(NH3)2 = 60.02 g/mol
2. Proportions the urea syntheres has a proportion of 1:1 with carbon dioxyde, so there is [tex]8.33x10^{4} mol[/tex] of CO(NH3)2
[tex]8.33x10^{4} mol[/tex] of CO(NH3)2 has [tex]5.00x10^{3} Kg[/tex]
[tex]Sample mass = n*molar mass[/tex]