Answer:
The angular momentum of the wheel is [tex]19.45\ kg-m^2/s[/tex].
Explanation:
It is given that,
Mass of the wheel, m = 2.73 kg
Radius of the wheel, r = 31 cm = 0.31 m
Angular speed of the wheel, [tex]\omega=1416\ rpm= 148.28\ rad/s[/tex]
We need to find its angular momentum. It is given by :
[tex]L=I\omega[/tex]
I is the moment of inertia of the wheel, [tex]I=\dfrac{mr^2}{2}[/tex]
[tex]L=\dfrac{mr^2}{2}\times \omega[/tex]
[tex]L=\dfrac{2.73\times (0.31)^2}{2}\times 148.28[/tex]
[tex]L = 19.45\ kg-m^2/s[/tex]
So, the angular momentum of the wheel is [tex]19.45\ kg-m^2/s[/tex]. Hence, this is the required solution.
