Answer:
(I). The store energy is 0.432 J.
(II). The energy density is 687.54 J/m³.
Explanation:
Given that,
Voltage = 12.0 V
Capacitor = 6.00 mf
Radius = 0.1 m
Distance = 10 mm
(I). We need to calculate the energy store
Using formula of store energy
[tex]U=\dfrac{1}{2}CV^2[/tex]
Where, C = capacitor
V = voltage
Put the value into the formula
[tex]U=\dfrac{1}{2}\times6.00\times10^{-3}\times(12.0)^2[/tex]
[tex]U=0.432\ J[/tex]
(II). We need to calculate the energy density
Using formula of energy density
[tex]\rho=\dfrac{E}{V}[/tex]
[tex]\rho=\dfrac{E}{\pi r^2 d}[/tex]
Where, r = radius
d = distance
Put the value into the formula
[tex]\rho=\dfrac{0.432}{2\times\pi\times(0.1)^2\times10\times10^{-3}}[/tex]
[tex]\rho=687.54\ J/m^3[/tex]
Hence, (I). The store energy is 0.432 J.
(II). The energy density is 687.54 J/m³.