contestada

Two bumper cars move in a straight line with the following equations of motion: x1 = -4.0 m + (1.1 m/s )t x2 = 8.8 m + (-2.9 m/s )t what time do they collide?

Respuesta :

MathPhys

Answer:

3.2 seconds

Explanation:

When the cars collide, they have the same position.

x₁ = x₂

-4 + 1.1t = 8.8 − 2.9t

4t = 12.8

t = 3.2

Cricetus

The time they collide will be "3.2 s".

The given equations are:

  • [tex]x_1 = -4.0 \ m + (1.1 \ m/s )t[/tex]
  • [tex]x_2 = 8.8 \ m + (-2.9 \ m/s )t[/tex]

According to the question, when the two bumper cars have the same position then,

→         [tex]x_1 = x_2[/tex]

By  putting the values, we get

→ [tex]-4.0 \ m + (1.1 \ m/s )t = 8.8 \ m + (-2.9 \ m/s )t[/tex]

→                [tex]-4.0 +1.1 t=8.8-2.9t[/tex]

→                  [tex]1.1 t+2.9 t=8.8+4.0[/tex]

→                               [tex]4t = 12.8[/tex]

→                                 [tex]t = \frac{12.8}{4}[/tex]

→                                 [tex]t = 3.2 \ s[/tex]

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