Question 6 (1 point)
A mini bag of skittles has 3 lemon, 4 grape, 4 orange, and 2 lime skittles. What is
the probability of randomly pulling an orange skittle out first and eating it and then
pulling a second orange skittle out of the bag next.
O 0.021
O 0.077
0.994
0.979

Respuesta :

chrry

Answer:

0.077

Step-by-step explanation:

(4/13 x 3/12) = 0.07692

= 0.077 (3s.f)

The probability of randomly pulling an orange skittle out first and eating it and again pulling a second orange skittle out of the bag next is 0.077.

What is probability?

Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event.

A mini bag of skittles has 3 lemon, 4 grape, 4 orange, and 2 lime skittles. The total number of skittles are,

[tex]\rm Skittles=3+4+4+2\\\rm Skittles=13[/tex]

Now randomly an orange skittle is pulled out. There are total 13 skittles in which 4 orange skittle. Thus, the prbability of this event is,

[tex]P_1=\dfrac{4}{13}[/tex]

The first orange is eaten. The orange remain in the bag are 3 and the total skittles remain are 12. Thus the probability of again picking the orange skittles is,

[tex]P_2=\dfrac{3}{12}[/tex]

By using the chain rule the probabily of both event is,

[tex]P=P_1\times P_2\\P=\dfrac{4}{13}\times\dfrac{3}{12}\\P\approx 0.077[/tex]

Hence, the probability of randomly pulling an orange skittle out first and eating it and again pulling a second orange skittle out of the bag next is 0.077.

Learn more about the probability here;

https://brainly.com/question/24756209