Respuesta :
Answer:
26.20 + 0.35m ≤ 200
Step-by-step explanation:
Let m = number miles of the driven
Given
$26.20 is the initial
Every mile cost $0.35
We have :
26.20 + 0.35m ≤ 200
Answer: The maximum number of miles would be 496 miles.
Step-by-step explanation:
Let the number of miles be 'm'.
Cost of per day = 426.20
Number of day = 1
Cost of per mile = $0.35
Total travel budget = $200
According to question, the inequality would be
[tex]26.20\times 1+0.35x\leq 200\\\\26.20+0.35x\leq 200\\\\0.35x\leq 200-26.20\\\\0.35x\leq 173.8\\\\x\leq \dfrac{173.8}{0.35}\\\\x\leq 496.57[/tex]
Hence, the maximum number of miles would be 496 miles.