Respuesta :
Answer :
(a) The IUPAC name for [tex]PBr_3[/tex] is phosphorous tribromide.
(b) The IUPAC name for [tex]N_2O[/tex] is dinitrogen oxide.
(c) The IUPAC name for [tex]Na_2S[/tex] is sodium sulfide.
(d) The IUPAC name for [tex]KMnO_4[/tex] is potassium permanganate(VII).
Explanation :
The nomenclature of covalent compound is given by:
1. The less electronegative element is written first.
2. The more electronegative element is written then, and a suffix is added with it. The suffix added is '-ide'.
3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on..
The nomenclature of ionic compounds is given by:
1. Positive ion is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.
(a) [tex]PBr_3[/tex] is a covalent compound because sharing of electrons takes place between phosphorous and bromine. Both the elements are non-metals and hence, will form covalent bond.
So, the IUPAC name for [tex]PBr_3[/tex] is phosphorous tribromide.
(b) [tex]N_2O[/tex] is a covalent compound because sharing of electrons takes place between nitrogen and oxygen. Both the elements are non-metals and hence, will form covalent bond.
So, the IUPAC name for [tex]N_2O[/tex] is dinitrogen oxide.
(c) [tex]Na_2S[/tex] is an ionic compound because sodium element is a metal and sulfur element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
So, the IUPAC name for [tex]Na_2S[/tex] is sodium sulfide.
(d) [tex]KMnO_4[/tex] is an ionic compound. The bond formed between a metal and a non-metal is always ionic in nature.
'Mn' is a transition metal and the oxidation state of 'Mn' is (+7)
The name of [tex]MnO_4[/tex] is permanganate.
So, the IUPAC name for [tex]KMnO_4[/tex] is potassium permanganate(VII).