Answer:
Perpendicular
Step-by-step explanation:
Given points P=(2,6) and Q=(4,5)
The line RS is y=2x-3.
Now we know that the line joining any two points (x1,y1) and (x2,y2) has slope m=[tex]\frac{y2-y1}{x2-x1}[/tex]
Now the slope of the line PQ is
m1=[tex]\frac{5-6}{4-2}[/tex]= -[tex]\frac{1}{2}[/tex]
We know that the slope of the line in the form y=mx+c is m
So the line RS has slope m2=2
Now two lines are parallel if m1=m2
And those two lines are perpendicular if [tex]m1*m2=-1[/tex]
here m1= -[tex]\frac{1}{2}[/tex] and m2=2
clearly [tex]m1*m2=-1[/tex]
Therefore the two given lines are perpendicular
