Answer:
The volume would be 364 L
Explanation:
This is an ideal gases problem and the specific situation is expansion. To find the final volume, we must study two states:
Initial
[tex]V_{1} =13.0\\P _{1}=28.0 atm\\[/tex]
Final
[tex]V_{2} =?\\P _{2}=1.00 atm\\[/tex]
Then, we use the equation of ideal gases and as temperature is constant, we can solve it as follows:
[tex]P_{1} V_{1}=nRT\\P_{2} V_{2}=nRT\\nRT=nRT \\ P_ {1} V_{1}=P_{2} V_{2}\\V_{2}=\frac{P_ {1} V_{1}}{P_{2} } \\V_{2}=\frac{28.0atm*13.0L}{1.00 atm} \\V_{2}=364L[/tex]
As you see, the final volume is greater than the initial, because the pressure drops and pressure and volume are inversely proportional.
