The acceleration of the car is [tex]9 m / \sec ^{2}[/tex]
Explanation:
Given:
Final velocity v = 0 m/s
Initial velocity u = 30 m/s
Stopping distance or displacement = 50 meters
To Find:
Acceleration of the car=?
Solution:
The third equation of motion is,
[tex]v^{2}-u^{2}=2 a s[/tex]
Substituting the known values,
[tex]v^{2}-u^{2}=2 a s[/tex]
[tex](30)^{2}-(0)^{2}=2(a)(50)[/tex]
[tex]900=100 a[/tex]
[tex]a=\frac{900}{100}[/tex]
[tex]a=9 m / \sec ^{2}[/tex]
