Answer:
4960 N
Explanation:
First, find the acceleration.
Given:
v₀ = 6.33 m/s
v = 2.38 m/s
Δx = 4.20 m
Find: a
v² = v₀² + 2aΔx
(2.38 m/s)² = (6.33 m/s)² + 2a (4.20 m)
a = -4.10 m/s²
Next, find the force.
F = ma
F = (1210 kg) (-4.10 m/s²)
F = -4960 N
The magnitude of the force is 4960 N.
Answer:
4,955.9 N
Explanation:
1/2 (m*v^2) = 1/2 (1210 x 6.33^2) = 24,241.7 J.
1/2 (1210 x 2.38^2) = 3,427 J.
(24,241.7 - 3,427) = 20,814.7J. of work done by the brakes.
(20,814.7/ 4.2m) = brake force of 4,955.9 N.
