Answer:
Explanation:
A )
A force of 310 N initiates motion in mass 45.2 kg so
Coefficient of static friction = force / normal reaction
= force / weight
= 310 / ( 45.2 x 9.8 )
= 0 .7
B )
A force of 231 N maintains uniform motion in mass 45.2 kg so
Coefficient of kinetic friction = force / normal reaction
= force / weight
= 231 / ( 45.2 x 9.8 )
= 0.52
C )
In motion, friction force acting = 231 N .
If F be the required force
F - 231 = 45.2 x 1.13 ( net force = mass x acceleration )
= 282.07 N
D )
On moon g = 1.62
Force of static friction there
= weight x coefficient of friction
= 45.2 x 1.62 x .7
= 51.25 N
Magnitude of push required = 51.25 N .