Answer:
Explained
Explanation:
let probability of getting attached by Hep(V) without benefit of new drug =P(A)
probability of getting attached by Hep(V) with new drug =P(B)
hence probability that Hep V attack are 2 given he is without benefit of drug =P(C|A) =[tex]\small e^{-\lambda }\lambda ^{x}/x! where \small \lambda=5[/tex] ,x=2
=0.084
and probability that Hep V attack are 2 given he is with new drug =P(C|B) [tex]=\small e^{-\lambda }\lambda ^{x}/x! where \small \lambda=3[/tex] ,x=2
=0.224
hence probability of Hep V attack are 2 =P(C) =P(A)*P(C|A) +P(B)*P(C|B) =0.25*0.084+0.224*0.75=0.189
from above probability that drug is beneficial given he had 2 Hep V attacks =P(B)*P(C|B)/P(C) =0.224*0.75/0.189 =0.8889