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A 6 μC point charge and a 9 μC point charge are initially infinitely far apart. How much work does it take to bring the 6 μC point charge to x = 3.0 mm, y = 0.0 mm and the 9 μC point charge to x = -3.0 mm, y = 0.0 mm? A 6 μC point charge and a 9 μC point charge are initially infinitely far apart. How much work does it take to bring the 6 μC point charge to x = 3.0 mm, y = 0.0 mm and the 9 μC point charge to x = -3.0 mm, y = 0.0 mm? 81 J 14 J 54 J 160 J

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Answer:

W = 80.91 J

Explanation:

First we identify the variables we use for the calculation.

[tex]W = \frac{Kq_1 q_2}{r}[/tex]

[tex]q_1 = -6 x 10^{-6 }C[/tex]

[tex]q_2 = - 9 x 10^{-6} C[/tex]

[tex]r = 6 mm = 6 x 10^{-3} m[/tex]

[tex]K = \frac{ \pi \epsilon_0}{4} = 8.99 x 109 N.m2/C2.[/tex]

In order to identify the missing variable, we proceed to calculate the work through the given formula. Substituting these values,

[tex]W = \frac{(8.99 x 10^9) * (- 9 x 10^{-6}) * (- 6 x 10^{-6})} {(6 x 10^{-3})}[/tex]

[tex]W = 80.91 J[/tex]

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