Haley needs to rent. Till 49.99 miles, Company B will be less expensive than company A.
Solution:
Given that
Haley needs to rent a moving van for the day.
Charges of company A are $75 plus $0.25 per miles
That means $75 is fixed price and $0.25 depends on travelling miles.
Charges of company B are $50 plus $0.75 per miles That means $50 is fixed price and $0.75 depends on travelling miles.
Need to calculate for how many miles is company B less expensive than company A.
Let’s assume for "x" miles company B is less expensive than company A.
Lets create expression for charges of each company for "x" miles.
For company A,
Fixed charges = $75
For 1 mile charges = $0.25
So for x miles = 0.25x
Total charges of company A for x miles [tex]=\mathrm{C}_{\mathrm{A}}=75+0.25 x[/tex]
For company B,
Fixed charges = $50
For 1 mile charges = $0.75
So for x miles = 0.75x
Total charges of company B for x miles [tex]=\mathrm{C}_{\mathrm{B}}=50+0.75 x[/tex]
we need to find value of x such that
[tex]\mathrm{C}_{\mathrm{B}}<\mathrm{C}_{\mathrm{A}}[/tex]
=> 50 + 0.75x < 75 + 0.25x
=> 0.75x - 0.25x < 75 – 50
=> 0.5x < 25
=> x < 50
So till 49.99 miles , Company B will be less expensive than company A.
At 50 miles charges of both the company will be same.