Answer:
3 adult tickets and 4 children's tickets.
Step-by-step explanation:
what i did was 9a+4c=43 I made the list of 1-6, 2-3, 3-4, 4-3, 5-2, and 6-1. This resembles a-c. I pluged them into the equation until i got 43=43 which would be 3-4.
Answer:
3 adult and 4 child tickets
Step-by-step explanation:
Let a = number of adult tickets
Let c = number of child tickets
We know two things:
[tex]a+c=7[/tex]
[tex]9a+4c=43[/tex]
First, solve the first equation for c :
[tex]a+c=7\\c=7-a[/tex]
Then, substitute the result into the second equation for c :
[tex]9a+4(7-a)=43\\9a+28-4a=43\\5a+28=43\\5a=15\\a=3[/tex]
Therefore, Mr. Ryan bought 3 adult tickets and 7 – 3 = 4 child tickets.
