Answer:
the answer is h= -3
Step-by-step explanation:
add 7 to -10 to find the value of h
Answer:
-3
Step-by-step explanation:
You can use [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] to find the slope of a line going through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].
I like to line up the points and subtract vertically. Then put 2nd difference over 1st difference.
(6,h)
minus
(7,-10)
------------
-1 h-(-10)
[tex]\frac{h-(-10)}{-1}[/tex]
This also said to be equal to -7:
[tex]\frac{h+10}{-1}=-7[/tex]
Multiply -1 on both sides:
[tex]h+10=7[/tex]
Subtract 10 on both sides:
[tex]h=7-10[/tex]
[texh=-3[/tex]
So if h=-3 then the slope of the line going through (6,h) and (7,-10) is -7.
Let's test it:
(6,-3)
minus
(7,-10)
----------
-1 7
So the slope is 7/-1=-7. This is the intended goal.
The check is good.
