jdoherty26
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I have a deck of 54 cards, and I deal all of the cards to x players, with each player getting y cards. If x is at least 2 and y is at least 5, then how many possible values of x are there?

Respuesta :

Answer:

4 possible values namely, (2 , 3, 6, 9 )

Step-by-step explanation:

When we factorise 54 we get,

[tex]54 = 2 \times 3 \times 3 \times 3 [/tex]

So, factors of 54 are, ( Except 1 and 54 (in pairs))

1. (2 , 27)  2. (3, 18) 3. (6 , 9)

So,

X  ∈ {2, 3, 6, 9}  but x ∉ { 27 , 18}  since y ∉ {2 ,3}

So, there are 4 possible values for x.

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