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A car is moving forward at 0.35 m/s. Attached to the rear-view mirror is a small air freshener with a string that is 15 cm
long. If the car were to suddenly come to a complete stop. What would be the maximum angle the air freshener string
would rotate through from a starting position of directly down?

Respuesta :

Answer:

[tex]16.6^{o}[/tex]

Explanation:

From the law of conservation of energy, the potential energy is converted to kinetic energy hence

[tex]mgh=0.5mv^{2}[/tex] where m is mass, g is acceleration due to gravity considered as 9.1m/s2, h is height and v is the velocity

[tex]gh=0.5v^{2}[/tex] and making h is the subject

[tex]h=0.5v^{2}/g=0.5(0.35^{2})/9.81= 0.006244 m or 0.6244 cm[/tex]

Also, [tex]h=L-Lcos\theta[/tex] where L is the length of string given as 15 cmand [tex]\theta[/tex] is the angle of inclination

[tex]h=L(1-cos\theta)[/tex]

[tex]1-cos\theta=\frac {h}{L}=\frac {0.6244}{15}=0.041624[/tex]

[tex]cos\theta=1-0.041624=0.958376[/tex]

[tex]\theta=cos^{-1}(0.958376)= 16.58932^{o}[/tex]

Therefore, [tex]\theta[/tex] is approximately [tex]16.6^{o}[/tex]