Respuesta :
(27, 3)
(1, 0)
Working;
Substituting the value of x;
x=27
y=log81
=1.9084
x=1
y=log 3
y=0.4771
(1, 0)
Working;
Substituting the value of x;
x=27
y=log81
=1.9084
x=1
y=log 3
y=0.4771
Answer:
(0,1) doesn't lie on the graph.
Step-by-step explanation:
We have been given the logarithmic equation [tex]y=\log_3(x)[/tex]
We can check which point lie on the graph of the given function by substituting x coordinates in the equation and find the corresponding y coordinate.
For x = 0
[tex]y=\log_3(0)\\\\y=\log_30[/tex]
The value of log 0, is undefined, Hence, we'll not get a real value for this x value.
Hence, (0,1) doesn't lie on the graph.
For x = 27
[tex]y=\log_3(27)\\\\y=\log_33^3\\\\y=3\log_33\\\\y=3[/tex]
Hence, (27,3) lie on the graph.
For x = 1
[tex]y=\log_3(1)\\\\y=0[/tex]
Hence, (1,0) lie on the graph.
Therefore, (0,1) doesn't lie on the graph.