Respuesta :
Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
Answer:
Option A. True.
Step-by-step explanation:
It is given in the triangle ABC
AD ≅ BD
AC ≅ BC
CD ≅ CD
By there facts Δ ADC ≅ ΔBDC
Therefore, ∠ADC ≅ ∠BDC
Since ∠ADC + ∠BDC = 180° [Angle on a straight line AB at point D]
and ∠ADC ≅ ∠BDC
so ∠ ADC + ∠ADC = 180°
2∠ADC = 180°
∠ADC = 90°
Therefore, AB is perpendicular to DC.
Hence, option A true is the answer.