Answer:
5/9
Step-by-step explanation:
To get the probability of getting a sum less than 7 from rolling two dice once, first one needs to draw the sample space for all the possible outcomes as shown below:
1. 2. 3. 4. 5. 6.
1. (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
2. (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
3. (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
4. (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
5. (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
6. (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
There are 15 events (underlined) that give a sum less than 7 out of the total of 36 possible events in the sample space.
Probability = _______Number of favorable outcomes_____
Total number of possible outcomes
Pr(Sum less than 7) = 15/36
Pr(Sum less than 7) = 5/9
