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A He–Ne laser illuminates a narrow, single slit that is 1850 nm wide. The first dark fringe is found at an angle of 20.0∘ from the central peak. 1) Determine the wavelength of the light from the laser. (Express your answer to three significant figures.)

Respuesta :

Answer:

Wavelength of light will be 632.73 nm

Explanation:

We have given width of the single slit [tex]d=1850nm-1850\times 10^{-9}m[/tex]

Angle is given as [tex]\Theta =20^{\circ}[/tex]

We have to find the wavelength of light for first dark fringe

We know that for dark fringe it is given that

[tex]dsin\Theta =n\lambda[/tex]

For first fringe n = 1

So [tex]1850\times 10^{-9}\times sin20^{\circ} =1\times \lambda[/tex]

[tex]\lambda =632.73nm[/tex]

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