Answer:
(a) Tangential velocity will be 38.648 m/sec
(b) Acceleration will be [tex]133.617m/sec^2[/tex]
Explanation:
We have given radius r = 11.2 m
Angular speed [tex]\omega =0.550rev/sec=0.550\times 2\pi =3.454rad/sec[/tex]
(a) We have to find the tangential velocity
We know that tangential velocity is given by
[tex]v_t=\omega r=3.454\times 11.2=38.684m/sec[/tex]
(b) We know that acceleration is given by
[tex]a=\frac{v^2}{r}=\frac{38.684^2}{11.2}=133.617m/sec^2[/tex]
