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An individual is heterozygous for two linked genes, but whether its genotype is AB/ab or Ab/aB is not known. The individual is crossed with ab/ab, and among the progeny are: 62 AB/ab; 13 Ab/ab; 18 aB/ab; 51 ab/ab. These results imply that the genotype of the doubly heterozygous parent was AB/ab.
A) True
B) False

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eyitbay

Answer: True

Explanation:

This is because the crossing with  recessive allele (ab ab) gives the percentage  proportion of  heterozygous  dominant allele as 62%AB and 51% ab.

This is test crossing . It is use to determine the genotype  of heterozyote dominant  alleles, where the phenotype can not be used to identify the genotypic proportion.

The  recessive allele(ab ab) above are used to determine the  proportion of inheritance of zygosity of the heterozygote allele  

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