Assume that a hat contains four bills: a $1 bill, a $5 bill, a $10 bill and a $20 bill. Two bills are to be selected at a random with replacement. find the probability that
a) both bills are $1 bill if the first selected is a $1 bill
b) both bills have a value greater than a $5 bill if the second bill is a $10 bill

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Answer:

a)1/4

b)1/2

Step-by-step explanation:

a) The selection is with replacement, then we already have 1 $ bill and in the hat again the four bills. What is the probability  of select 1$ bill ? well it is 1/4.

The point here is,  replacement condition make the second trial totally independent of the first one

b)Following the same reasoning now we have selected a 10 $ bill, and we have two possibles positive outcome a 10 $ and a 20 $ bill and a total of 4 outcomes th th probability is 1/2

The probabilities are:

a) 1/16

b) 1/8.

How to find the probabilities?

We assume that all the bills have the same probability of being randomly selected.

a) Then the probability of randomly selecting a $1 bill is equal to the number of $1 bills on the hat divided by the total number of bills.

There is one $1 bill on the hat, and 4 bills in total, so the probability is:

p = 1/4.

Then you return the $1 bill to the hat and want to draw it again, with the same probability as before.

q = 1/4.

The joint probability is the product of the individual probabilities, so we have:

P = p*q = (1/4)*(1/4) = 1/16.

b) There are 2 bills that have a larger value than $5, then the probability for the first draw is:

p = 2/4

For the second draw, we must get the $10 bill, and the probability of getting it is:

q = 1/4.

The joint probability is:

P = p*q = (2/4)*(1/4) = 1/8.

If you want to learn more about probability, you can read:

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