Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is switched off in 1.00 ms, inducing a 9.00 V emf in the other. What is their mutual inductance?

Respuesta :

Answer:

Mutual inductance will be [tex]M=1.8\times 10^{-3}Hennry[/tex]

Explanation:

We have given induced current [tex]\Delta i=5A[/tex]

Time is given as [tex]t=1ms=10^{-3}sec[/tex]

We have to find the mutual inductance between the coils

Induced emf is given as e = 9 volt

We know that induced emf is given by

[tex]e=M\frac{\Delta i}{\Delta t}[/tex]

[tex]9=M\times \frac{5}{10^{-3}}[/tex]

[tex]M=1.8\times 10^{-3}Hennry[/tex]