Respuesta :
Answer:22,833.12 N
Explanation:
Given
Velocity of Jet [tex]v=201 m/s[/tex]
Velocity of Exhaust gases [tex]u=669 m/s[/tex]
Rate of intake of air [tex]\frac{\mathrm{d} M_a}{\mathrm{d} t}=44.1 kg/s[/tex]
Rate at which Fuel is burned is [tex]\frac{\mathrm{d} M_f}{\mathrm{d} t}=3.28 kg/s[/tex]
Rate of change of mass in Rocket [tex]\frac{\mathrm{d} M}{\mathrm{d} t}=\frac{\mathrm{d} M_a}{\mathrm{d} t}+\frac{\mathrm{d} M_f}{\mathrm{d} t}=44.1+3.28=47.38 kg/s[/tex]
Thrust on Rocket is given by
[tex]F=\frac{\mathrm{d} M}{\mathrm{d} t}u-\frac{\mathrm{d} M_a}{\mathrm{d} t}v[/tex]
[tex]F=47.38\times 669-44.1\times 201[/tex]
[tex]F=31,697.22-8864.1=22,833.12 N[/tex]
Answer:
Find the delivered power.
Answer in units of W.
Explanation:
