Answer:
Pressure, [tex]P=2.05\times 10^6\ Pa[/tex]
Explanation:
Given that,
The combined mass of the man and chair is 95.0 kg, m = 95 kg
The radius of the circular leg of the chair, r = 0.6 cm
Area of the 4 legs of the chair, [tex]A=4\times \pi r^2[/tex]
Let P is the pressure each leg exert on the floor. The total force acting per unit area is called pressure exerted. Its expression is given by :
[tex]P=\dfrac{F}{A}[/tex]
[tex]P=\dfrac{mg}{4\times \pi r^2}[/tex]
[tex]P=\dfrac{95\times 9.8}{4\times \pi (0.6\times 10^{-2})^2}[/tex]
[tex]P=2.05\times 10^6\ Pa[/tex]
So, the pressure exerted by each leg on the floor is [tex]2.05\times 10^6\ Pa[/tex]. Hence, this is the required solution.
