Answer:
d) Decreasing the temperature at constant volume
Explanation:
if we assume ideal gas behaviour, since the concentration of the gas is proportional to its pressure at constant temperature
(from the ideal gas law PV =nRT or P= CRT), the equilibrium constant in terms of pressure will be
Kp = (p² HCl *p² I2)/(p² HI *p² CL2)
from Dalton's law : pi = P*xi
Kp = (P²*x² HCl *P* x I2)/(P*x HI *P²x² CL2) = (x² HCl * x I2)/(x HI *x² CL2)
since Kp does not change because the T is constant and it does not depend on pressure → the equilibrium will not change due to changes in pressure caused by reductions or increases in volume at constant pressure and composition
also since the reaction is exothermic → an increase in temperature will displace the equilibrium towards the reactants , and thus decreasing the moles of I2 at equilibrium
this can be seen from van't hoff equation :
d ln (K) /dT= ΔH/RT² , since ΔH>0 → K diminishes with increase in temperature
on the other hand, a decrease in temperature will displace the equilibrium towards the products , and thus increasing the moles of I2 at equilibrium