Respuesta :
Answer:
The solution is not possible for the number of chair to be sold 18 , It is only possible if the number of chair to be sold is 11 and the number of tables to be sold is 9 .
Step-by-step explanation:
Given as :
The cost of each chairs = $ 150
The cost of each tables = $ 350
The maximum number of chair and table can ship = 20
The minimum selling amount of chairs and tables = $ 4800
Let The number of chair to be ship = C
And The number of table to be ship = T
So , According to question
C + T = 20 .......1
And $ 150 × C + $ 350 × T = $ 4800 ....2
So, From first eq
$ 150 × ( C + T ) = $ 150 × 20
Or, $ 150 C + $ 150 T = $ 3000
So, Solving eq
( $ 150 × C + $ 350 × T ) - ( $ 150 C + $ 150 T ) = $ 4800 - $ 3000
Or, ( $ 150 C - $ 150 C ) ( $ 350 T - $ 150 T ) = $ 1800
Or, 0 + $ 200 T = $ 1800
Or, T = [tex]\frac{1800}{200}[/tex]
∴ Number of Tables T = 9
So, Number of chairs C = 20 - T = 20 - 9 = 11
Thus to meet the requirement The number of Tables to be sold = 9 and the number of chairs to be sold = 11
But , If the number of chair to be sold = 18
And Since The maximum of pieces of furniture to be sell = 20
So, The number of tables to be sold = T = 20 - 18 = 2
∴ For table T = 2 And chair C = 18
Let check the net worth
I.e ( $ 150 × C + $ 350 × T )
Or, ( $ 150 × 18 + $ 350 × 2 )
Or, $ 2700 + $ 700 = $ 3400
But The company must sell the furniture of net worth at least $ 4800 , So this is not possible to sell 18 chair .
Hence The solution is not possible for the number of chair to be sold 18 , It is only possible if the number of chair to be sold is 11 and the number of tables to be sold is 9 . Answer
