Answer:
one-quarter as strong
Explanation:
Coulomb's law gives the mathematical expression to calculate the electrical force (F) between the charge of the nucleus (q₊) and the charge of an electron (q₋) separated by a distance (r).
[tex]F=\frac{k.q_{+}.q_{-}}{r^{2} }[/tex]
where,
k is the Coulomb's constant
The force between the nucleus and an electron in the level 1 is:
[tex]F_{1}=\frac{k.q_{+}.q_{-}}{r_{1}^{2} }[/tex]
Considering the distance to an electron from n = 2 is twice as great as the distance to an electron from n = 1, the force between the nucleus and an electron in the level 2 is:
[tex]F_{2}=\frac{k.q_{+}.q_{-}}{r_{2}^{2} }=\frac{k.q_{+}.q_{-}}{(2r_{1})^{2} }=\frac{1}{4} \frac{k.q_{+}.q_{-}}{(r_{1})^{2} }=\frac{1}{4}F_{1}[/tex]
