A factor of f(x) is (x + 1) must be true ⇒ 2nd answer
Step-by-step explanation:
In a quadratic equation y = ax² + bx + c, the roots of it are:
- The values of x when y = 0
- They can called the x-intercepts
- If the roots of it are m and n, then the factors of the equation are (x - m) and (x - n)
∵ -1 is a root of f(x)
∵ The roots of f(x) are the values of x when f(x) = 0
∴ At f(x) = 0, x = -1
When f(x) = 0, then all factors of f(x) must be equate by 0
∵ f(x) = 0
∵ x = -1 ⇒ when f(x) = 0
- Add to sides by 1
∵ x + 1 = 0
∴ (x + 1) is one factor of f(x)
A factor of f(x) is (x + 1) must be true
Learn more:
You can learn more about the x-intercepts in brainly.com/question/1502731
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