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A 2 kg soccer ball is traveling 28.62m/s when it hits the wall and bounces off of the wall with a velocity of 20 m/s. If the wall exerted an average force of 652.36N on the ball, how long was the ball in contact with the wall?

Respuesta :

Answer:

0.149 s or 0.15 s

Explanation:

let initially ball is moving towards left  hence initial velocity = - 28.62 m/s

final velocity as ball moves right = +20 m/s

force  = rate of change in momentum

force  = mass × change in velocity / time

or time = mass × change in velocity / force

    time = 2× ( 20 -( -28.62)) / 652.36

    time  = 2× ( 20  +28.62)) / 652.36  

time  =   2× 48 .62/652.36

 time =  0.149 s or 0.15 s

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