The applied pressure at the end of this process is P = -2.859atm
Explanation:
Write down the given values
there are concentration of two solutions
S1 = 0.053 M
S2 = 0.170 M
Temperature (T) = 23°C
that is written as 298 K
it can be solved by multiplying ans subtracting the values
P=MR1-MR2
0.053 M * 0.082 * 298 - 0.170 M * 0.082 * 298
= 1.295 - 4.15412
P = -2.859atm