Respuesta :
Answer:
Option E density
Explanation:
This is actually pretty easy to explain. At the beggining it states that at STP which are 1 atm and 273 K, we have two samples of H2 but in different quantities. So using the ideal gas equation, we calculate the volume of each gas:
PV = nRT (1)
Where:
P: pressure in atm
V: volume in L
n: moles
R: gas constant which is 0.082 L atm / K mol
T: temperature in K
So from this equation, we solve for V:
V = nRT/P
Replacing data for both samples we have:
V1 = 0.5 * 0.082 * 273 / 1 = 11.19 L
V2 = 1 * 0.082 * 273 / 1 = 22.38 L
Now, to verify that is option E, let's write the expression for density:
d = m/V (2)
Where:
d: density
m: mass
To calculate the mass, we use the molar weight of hydrogen (2 g/mol) and the moles of the samples so:
m1 = 0.5 * 2 = 1 g
m2 = 1 * 2 = 2 g
Now, replacing in (2):
d1 = 1 / 11.19 = 0.0893 g/L
d2 = 2 / 22.38 = 0.0893 g/L
As d1 = d2 we can conclude that option E is the correct option.
Here, we are required to identify which property is constant for a 0.50 mol sample of H2 gas and a separate 1.0 mol sample of O2 gas at standard temperature and pressure.
- The correct answer is Choice E: density.
According to the question; at Standard pressure and temperature of values 1 atm and 273 K, we have two samples of Hydrogen, H2 in different quantities. So using the ideal gas equation, we calculate the volume of each gas:
PV = nRT……....…….......................ideal gas equation.
Where:
P: pressure in atm
V: volume in L
n: moles
R: gas constant which is 0.082 L³ atm / K mol
T: temperature in K
So from this equation, we solve for V:
V = nRT/P
Replacing data for both samples we have:
V1 = 0.5 * 0.08205 * 273 / 1 = 11.20 L
V2 = 1 * 0.08205 * 273 / 1 = 22.40 L
Now, to verify that is option E, let's write the expression for density:
d = m/V ...............................density = mass/volume
The molar mass of hydrogen (2 g/mol) and the no. moles of the samples can be used to evaluate the mass of each specie so:
m1 = n × M = 0.5 * 2 = 1 g
m2 = n× M = 1 * 2 = 2 g
Therefore, by substituting m into d = m/V; we have;
D1 = 1 / 11.20 = 0.0893 g/L
D2 = 2 / 22.40 = 0.0893 g/L
Therefore, since D1 = D2, we can conclude that Density is constant.
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