Respuesta :
Answer:
The value remains the same.
Step-by-step explanation:
using the expression: [tex](x + 1)^{2}[/tex],
where x = 2
substitute for x in the expression;
[tex](2 + 1)^{2}[/tex]
= [tex](3)^{2}[/tex]
=9
The value of the expression before expansion = 9
Lets expand the expression: [tex](x + 1)^{2}[/tex]
= (x + 1) (x + 1)
= [tex]x^{2}[/tex] + 2x + 1
substitute for x in the expression
= [tex]2^{2}[/tex] + 2(2) + 1
= 4 + 4 + 1 = 9
The value of the expansion after expansion = 9
The value remains the same before and after expansion.
The value of an expression, before and when it is expanded will be always same.
Let us consider that an expression,
[tex]f(x)=(x-1)^{2}[/tex]
Substitute x = 2 in above relation.
[tex]f(2)=(2-1)^{2}=1[/tex]
Now expand,
[tex]f(x)=(x-1)^{2}=x^{2} -2x+1\\\\f(2)=2^{2}-2*2+1\\\\f(2)=4-4+1\\\\f(2)=1[/tex]
Hence, the value of an expression, before and when it is expanded will be always same.
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