A linear enzyme is formed by four alpha and two beta protein subunits. How manydifferent arrangements are there?

Respuesta :

Answer:

15

Step-by-step explanation:

We are given that

Number of alpha protein subunits=4

Number of beta protein subunits=2

Total number of protein sub-units=2+4=6

We have to find the number of different arrangements are there.

When r identical letters and y identical letters and total object are n then arrangements are

[tex]\frac{n!}{r!x!}[/tex]

n=6,r=2,x=4

By using the formula

Then, we get

Number of different arrangements =[tex]\frac{6!}{2!4!}[/tex]

Number of different arrangements=[tex]\frac{6\times 5\times 4!}{2\times 1\times 4!}[/tex]

Number of different arrangements=15

Hence, different arrangements are there= 15