Answer:
Explanation:
Given
height [tex]h=6.2 km[/tex]
Initial temperature [tex]T_1=30^{\circ}C[/tex]
Specific heat of lead [tex]c=126 J/kg-^{\circ}C[/tex]
Melting Point of Lead [tex]T_m=130^{\circ}C[/tex]
Here Potential Energy is converted to heat energy to melt the lead ball
Sphere ball will first will be heated to [tex]130^{\circ}C[/tex] then it starts melting
thus
[tex]mgh=mc\Delta T+mL[/tex]
where [tex]L=latent\ heat\ of\ fusion[/tex]
[tex]\Delta T=[/tex]change in Temperature
[tex]gh=c\Delta T+L[/tex]
[tex]9.8\times 6.2\times 1000=126\times (130-30)+L[/tex]
[tex]L=48,160\ J/kg [/tex]
[tex]L=48.16\ kJ/kg[/tex]
