Respuesta :
Answer:
6 hours
Step-by-step explanation:
You can set up a chart:
R T D
O 300 1+x ~ O=out B=back R=Rate/Speed T=time D=distance
B 350 x ~
The distance is the same. On the way out the speed was 300 mph, so you can see where that is on the chart. And the speed back was 350 mph. It took an extra hour on the way out than on the way back, so you can call the way back's time x and then say the way out's time was x+1.
It's important to know that R times T = D
Therefore we can say 300(x+1)=D and 350(x)=D
Since the distance is the same, 300(x+1)=350(x)
Solve:
300(x+1)=350x
300x+300=350x
50x=300
x=6
Therefore, the trip out took 6 hours.
I hope that helps! :)
Answer:the trip out took 7 hours
Step-by-step explanation:
Distance travelled = speed × time
Let t represent the time it took the plane to travel from California.
It took one hour on the way out than it did on the way back. This means that the time it took the plane to return would be t - 1
The plane's average speed out ward 300 mph. Distance travelled when going out would be
300 × t = 300 = 300t
The speed on the way back was 350mph. Distance travelled when returning would be
350(t - 1) = 350t - 350
Since the distance is the same, it means that
300t = 350t - 350
350t - 300t = 350
50t = 350
t = 350/50 = 7
Time taken to go out is 7 hours
