Answer:
Step-by-step explanation:
I used the displacement equation from Physics to solve this cuz it was easiest to do it that way. The displacement equation is
Δx = v₀t + .5at²
where Δx is the displacement of the ball in feet, v₀ is the initial upwards velocity in feet/sec, a is the acceleration due to gravity (which has a constant value of -32 ft/sec/sec), and t is time in seconds.
If the ball lands right back where it started, its displacement is 0. We know the pull of gravity, and we are given the time as 3 seconds. Filling in our equation and solving for the velocity:
[tex]0=v(3)+.5(-32)(3)^2[/tex] and
0 = 3v - 144 and
144 = 3v so
v = 48 ft/sec
