a) The change in ball's momentum is 3 kg m/s downfield
b) The force exerted is 15 N downfield
Explanation:
a)
The change in momentum of an object is given by:
[tex]\Delta p = m(v-u)[/tex]
where:
m is the mass of the object
u is the initial velocity
v is the final velocity
For the ball in this problem, we have:
m = 0.50 kg (mass)
u = 10 m/s (initial velocity)
v = 16 m/s (final velocity has same sign of initial velocity, since they are both downfield)
Therefore, the change in momentum is
[tex]\Delta p =(0.50)(16-10)=3 kg m/s[/tex]
b)
The constant force exerted on the ball can be found by using the impulse theorem, which states that the impulse exerted on the ball (the product of force and time interval) is equal to the change in momentum:
[tex]F\Delta t = \Delta p[/tex]
where
F is the magnitude of the force
[tex]\Delta t[/tex] is the duration of the collision
For the ball in this problem, we have:
[tex]\Delta t = 0.2 s[/tex] (duration of the collision)
[tex]\Delta p = 3 kg m/s[/tex] (change in momentum)
Therefore, the force exerted on the ball is:
[tex]F=\frac{\Delta p}{\Delta t}=\frac{3}{0.2}=15 N[/tex]
Learn more about change in momentum:
brainly.com/question/9484203
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