Respuesta :
Answer:
(a) 900
(b) 648
(c) 180
(d) 600
Step-by-step explanation:
If there are no restrictions, there are 10 possible values for each digit of a three-digit number.
(a) The leading digit cannot be zero
There are 9 options for the first digit and 10 for the remaining digits.
[tex]n=9*10*10 = 900[/tex]
(b) The leading digit cannot be zero and no repetition of digits is allowed.
[tex]n=9*9*8=648[/tex]
(c) The leading digit cannot be zero and the number must be a multiple of 5.
If a number is a multiple of five, it must end in 0 or 5
[tex]n=9*10*2=180[/tex]
(d) The number is at least 400.
If the number is at least 400, the first digit can only be 4, 5, 6, 7, 8 or 9. There are no restrictions for the remaining digits.
[tex]n=6*10*10=600[/tex]
The number of three-digit numbers that can be formed under each condition are as follows;
- (a) 900
- (a) 900(b) 648
- (a) 900(b) 648(c) 180
- (a) 900(b) 648(c) 180(d) 600
Provided there are no restrictions, there are 10 possible outcomes for each digit of a three-digit number.
For case (a): The leading digit cannot be zero
There are 9 options for the first digit and 10 for the remaining digits.
- 9 × 10 × 10 = 900
For case (b): The leading digit cannot be zero and no repetition of digits is allowed.
In essence, the first digit has 9 outcomes, the second is supposed to be 10, but now has 9 since no repetition is allowed, while the 3rd digit now has 8.
- 9 × 9 × 8 = 648
For case (c): The leading digit cannot be zero and the number must be a multiple of 5.
If a number is a multiple of five, it must end in 0 or 5
- 9 × 10 × 2 = 180
For case (d): The number is at least 400.
Provided the number is at least 400, the first digit can only be 4, 5, 6, 7, 8 or 9. There are no restrictions for the remaining digits.
- 6 × 10 × 10 = 600
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