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A loop of wire carrying a current of 2.0 A is in the shape of a right triangle with two equal sides, each 15 cm long. A 0.7 T uniform magnetic field is parallel to the hypotenuse. The total magnetic force on the two equal sides has a magnitude of:

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Answer:

The total magnetic force is 0.297 N.

Explanation:

Given that,

Current = 2.0 A

Length of each side = 15 cm

Magnetic field = 0.7 T

A loop of wire is in the shape of a right triangle with two equal sides.

The angle between the magnetic field and both the sides of the triangle is 45 degrees.

We need to calculate the total magnetic force

Using formula of magnetic force

[tex]F=2BIl\sin\theta[/tex]

Where, B = magnetic field

I = current

L- length

Put the value into the formula

[tex]F=2\times0.7\times2.0\times15\times10^{-2}\sin45[/tex]

[tex]F=0.297\ N[/tex]

Hence, The total magnetic force is 0.297 N.

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