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A 0.683 kg mass moves in SHM at the end of a spring. It takes 1.41 s to move from the position with the spring fully extended to the position with the spring fully compressed. What is the spring constant?

Respuesta :

Answer:

Spring constant of the spring will be equal to 9.255 N /m          

Explanation:

We have given mass m = 0.683 kg

Time taken to complete one oscillation is given T = 1.41 sec

We have to find the spring constant of the spring

From spring mass system time period is equal to [tex]T=2\pi \sqrt{\frac{m}{K}}[/tex], here m is mass and K is spring constant

So [tex]1.41=2\times 3.14\sqrt{\frac{0.683}{K}}[/tex]

[tex]0.2245=\sqrt{\frac{0.683}{K}}[/tex]

Squaring both side

[tex]0.0504=\frac{0.4664}{K}[/tex]

[tex]K=9.255N/m[/tex]

So spring constant of the spring will be equal to 9.255 N /m

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