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Using the two circuits, calculate i1, i2, v1, v2, the power (PR) being dissipated (absorbed) by the resistor, and the conductance (PG). Assume that Is= 2.7A, Vs= 1.5 V, R= 270 Ω, and G= 0.27 S

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Answer:

[tex]i_1=2.7\:\:A\\i_2=0.405\:\:A\\v_1=729\:\:V\\v_2=v_S=1.5\:\:V\\[/tex]

Explanation:

[tex]i_1=i_S=2.7\:\:A\\v_1=i_1R=2.7*270=729\:\:V\\v_2=v_S=1.5\:\:V\\i_2=v_2G=1.5*0.27=0.405\:\:A[/tex]

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