Answer:
The fox leaves the snow at 3.99 m/s
Explanation:
Hi there!
The equation of height and velocity of the fox are the following:
h = h0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
h = height of the fox at a time t.
h0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.81 m/s considering the upward direction as positive)
v = velocity of the fox at a time t.
We know that at the maximum height of the fox, its velocity is zero, so using the equation of velocity we can obtain an expression of v0 in function of t:
v = v0 + g · t
At the maximum height, v = 0
0 = v0 + g · t
Solving for v0:
-g · t = v0
We know the maximum height of the fox, 0.810 m. So, using the equation of height and replacing v0 by (-g · t), we can obtain the time at which the fox is at the maximum height and then calculate the initial velocity:
h = h0 + v0 · t + 1/2 · g · t²
When t is the time at which the fox is at the maximum height, h = 0.810 m and v0 = (-g · t). Let´s consider the ground as the origin of the frame of reference so that h0 = 0.
0.810 m = (-g · t) · t + 1/2 · g · t²
0.810 m = -g · t² + 1/2 · g · t²
0.810 m = - 1/2 · g · t²
t² = -2 · 0.810 m / -9.81 m/s²
t = 0.406 s
And the initial velocity will be:
v0 = -g · t
v0 = -(-9.81 m/s²) · 0.406 s
v0 = 3.99 m/s
The fox leaves the snow at 3.99 m/s