Answer:
The probability that Jenny picked a gray tile with her second pick given that she picked a blue tile with her first pick = 0.25
Step-by-step explanation:
i.) there are 6 gray tiles and 3 blue tiles
ii) the probability that Jenny picked a blue tile first is given by
[tex]\frac{number\hspace{0.1cm} of \hspace{0.1cm} blue\hspace{0.1cm} tiles }{total \hspace{0.1cm}number\hspace{0.1cm} of \hspace{0.1cm}tiles\hspace{0.1cm} } = \frac{3}{9} = \frac{1}{3}[/tex]
iii) the probability that Jenny picked a gray tile with her second pick without replacing the first tile[tex]\frac{number\hspace{0.1cm} of \hspace{0.1cm} blue\hspace{0.1cm} tiles }{total \hspace{0.1cm}number\hspace{0.1cm} of \hspace{0.1cm}tiles\hspace{0.1cm} } \times \frac{number\hspace{0.1cm} of \hspace{0.1cm} gray\hspace{0.1cm} tiles }{total \hspace{0.1cm}number\hspace{0.1cm } of \hspace{0.1cm}tiles\hspace{0.1cm} - 1 } = \frac{3}{9} \times \frac{6}{8} = \frac{1}{3} \times \frac{3}{4} = \frac{1}{4} = 0.25[/tex]
The probability that Jenny picked a gray tile with her second pick given that she picked a blue tile with her first pick = 0.25
