Answer:
2 cubic meters
Explanation:
Suppose ideal gas, when the temperature stays constant, then the product of pressure and volume is the same as before
[tex]P_1V_1 = P_2V_2[/tex]
where [tex]P_1 = 4 atm, V_1 = 0.5m^3[/tex] are the pressure and volume of the gas before. [tex]P_2 = 1 atm, V_2[/tex] are the pressure and volume of the gas after. We can solve for the volume after
[tex]V_2 = \frac{P_1V_1}{P_2} = \frac{4*0.5}{1} = 2 m^3[/tex]
